What is the integral of (-2)/(z^3) ?

The integral of (-2)/(z^3) is 1/(z^2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (-2)/(z^3)

integral

\frac{- 2}{z ^{3}}

\frac{1}{z ^{2}} + C

Solution steps

\int \frac{- 2}{z ^{3}} d z

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int \frac{1}{z ^{3}} d z

Apply the Power Rule

= - 2 (- \frac{1}{2 z ^{2}})

Simplify

- 2 (- \frac{1}{2 z ^{2}}) : \frac{1}{z ^{2}}

= \frac{1}{z ^{2}}

Add a constant to the solution

= \frac{1}{z ^{2}} + C