What is the integral of ((9^9)^9)^x ?

The integral of ((9^9)^9)^x is (3^{162x-4})/(2ln(3))+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of ((9^9)^9)^x

integral

((9^{9})^{9})^{x}

\frac{3 ^{162 x - 4}}{2 ln ( 3 )} + C

Solution steps

\int ((9^{9})^{9})^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= \frac{( ( 9 ^{9} ) ^{9} ) ^{x}}{ln ( ( 9 ^{9} ) ^{9} )}

Simplify

\frac{( ( 9 ^{9} ) ^{9} ) ^{x}}{ln ( ( 9 ^{9} ) ^{9} )} : \frac{3 ^{162 x - 4}}{2 ln ( 3 )}

= \frac{3 ^{162 x - 4}}{2 ln ( 3 )}

Add a constant to the solution

= \frac{3 ^{162 x - 4}}{2 ln ( 3 )} + C

What is the integral of ((9^9)^9)^x ?
The integral of ((9^9)^9)^x is (3^{162x-4})/(2ln(3))+C