What is the tangent of y=x+sqrt(x),(4,6) ?

The tangent of y=x+sqrt(x),(4,6) is y= 5/4 x+1

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tangent of y=x+sqrt(x),(4,6)

tangent of

y = x + x, (4, 6)

y = \frac{5}{4} x + 1

Solution steps

Find the slope of

y = x + x : \frac{d y}{d x} = 1 + \frac{1}{2 x}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{5}{4}

Find the line with slope m=

\frac{5}{4}

and passing through

(4, 6) : y = \frac{5}{4} x + 1

y = \frac{5}{4} x + 1

What is the tangent of y=x+sqrt(x),(4,6) ?
The tangent of y=x+sqrt(x),(4,6) is y= 5/4 x+1