What is the derivative of 4/(x+3) ?

The derivative of 4/(x+3) is -4/((x+3)^2)

What is the first derivative of 4/(x+3) ?

The first derivative of 4/(x+3) is -4/((x+3)^2)

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\frac{d}{d x} (\frac{4}{x + 3})

- \frac{4}{( x + 3 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{x + 3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{x + 3})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((x + 3)^{- 1})

Apply the chain rule:

- \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

= - \frac{1}{( x + 3 ) ^{2}} \frac{d}{d x} (x + 3)

\frac{d}{d x} (x + 3) = 1

= 4 (- \frac{1}{( x + 3 ) ^{2}} \cdot 1)

Simplify

4 (- \frac{1}{( x + 3 ) ^{2}} \cdot 1) : - \frac{4}{( x + 3 ) ^{2}}

= - \frac{4}{( x + 3 ) ^{2}}

What is the derivative of 4/(x+3) ?
The derivative of 4/(x+3) is -4/((x+3)^2)
What is the first derivative of 4/(x+3) ?
The first derivative of 4/(x+3) is -4/((x+3)^2)