What is the solution for (d-3)^2*y=2e^{4x} ?

The solution for (d-3)^2*y=2e^{4x} is y=c_{1}e^{3x}+c_{2}xe^{3x}+2e^{4x}

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(d-3)^2*y=2e^{4x}

(d - 3)^{2} \cdot y = 2 e^{4 x}

y = c_{1} e^{3 x} + c_{2} x e^{3 x} + 2 e^{4 x}

Solution steps

(d - 3)^{2} y = 2 e^{4 x}

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} x e^{3 x} + 2 e^{4 x}

y = c_{1} e^{3 x} + c_{2} x e^{3 x} + 2 e^{4 x}

(d^{2} - 4) \cdot y = x^{2}

y^{^{''}} + y^{^{'}} + 3 y = 9 x^{2} + 3

(d^{2} + 3 d + 2) y = e^{- x} + cos (x)

(d^{2} - 2 d + 1) \cdot y = a^{x} \cdot x^{2}

(d^{3} - 5 d^{2} + 8 d - 4) \cdot y = e^{2 x} + 2 e^{x} + 3 e^{- x} + 2

What is the solution for (d-3)^2*y=2e^{4x} ?
The solution for (d-3)^2*y=2e^{4x} is y=c_{1}e^{3x}+c_{2}xe^{3x}+2e^{4x}