derivative f(x)=-9.8x^2+2x+1

Lösung

ableitung von

f (x) = - 9.8 x^{2} + 2 x + 1

- 19.6 x + 2

Schritte zur Lösung

\frac{d}{d x} (- 9.8 x^{2} + 2 x + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (9.8 x^{2}) + \frac{d}{d x} (2 x) + \frac{d}{d x} (1)

\frac{d}{d x} (9.8 x^{2}) = 19.6 x

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (1) = 0

= - 19.6 x + 2 + 0

Vereinfache

= - 19.6 x + 2

\int \frac{1}{arcsin ( x ) 1 - x ^{2}} d x

\frac{\partial}{\partial x} (x^{2} + x y + y^{2} + 2 x - y)

\frac{d}{d t} (- cos (2 t))

\int (2 x^{4} - 8 x^{3}) \cdot e^{- 3 x} d x

(2 x y) d y + (x^{2} + y^{2}) d x = 0