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人気のある微分積分 >

integral of sec(1/2)ztan(1/2)z

解

\int sec (\frac{1}{2}) z tan (\frac{1}{2}) z d z

解

\frac{1}{3} sec (\frac{1}{2}) tan (\frac{1}{2}) z^{3} + C

解答ステップ

\int sec (\frac{1}{2}) z tan (\frac{1}{2}) z d z

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= sec (\frac{1}{2}) tan (\frac{1}{2}) \cdot \int zz d z

簡素化

zz : z^{2}

= sec (\frac{1}{2}) tan (\frac{1}{2}) \cdot \int z^{2} d z

べき乗則を適用する

= sec (\frac{1}{2}) tan (\frac{1}{2}) \frac{z ^{3}}{3}

簡素化

sec (\frac{1}{2}) tan (\frac{1}{2}) \frac{z ^{3}}{3} : \frac{1}{3} sec (\frac{1}{2}) tan (\frac{1}{2}) z^{3}

= \frac{1}{3} sec (\frac{1}{2}) tan (\frac{1}{2}) z^{3}

定数を解答に追加する

= \frac{1}{3} sec (\frac{1}{2}) tan (\frac{1}{2}) z^{3} + C

グラフ

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