What is the integral of (x+e^{2x})/(x^2+e^{2x)} ?

The integral of (x+e^{2x})/(x^2+e^{2x)} is 1/2 ln|x^2+e^{2x}|+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (x+e^{2x})/(x^2+e^{2x)}

\int \frac{x + e ^{2 x}}{x ^{2} + e ^{2 x}} d x

\frac{1}{2} ln x^{2} + e^{2 x} + C

Solution steps

\int \frac{x + e ^{2 x}}{x ^{2} + e ^{2 x}} d x

Apply u-substitution

= \int \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= \frac{1}{2} ln ∣ u ∣

Substitute back

u = x^{2} + e^{2 x}

= \frac{1}{2} ln x^{2} + e^{2 x}

Add a constant to the solution

= \frac{1}{2} ln x^{2} + e^{2 x} + C

What is the integral of (x+e^{2x})/(x^2+e^{2x)} ?
The integral of (x+e^{2x})/(x^2+e^{2x)} is 1/2 ln|x^2+e^{2x}|+C