What is the integral of cot(1/2)x ?

The integral of cot(1/2)x is 1/2 cot(1/2)x^2+C

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integral of cot(1/2)x

\int cot (\frac{1}{2}) x d x

\frac{1}{2} cot (\frac{1}{2}) x^{2} + C

Solution steps

\int cot (\frac{1}{2}) x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= cot (\frac{1}{2}) \cdot \int x d x

Apply the Power Rule

= cot (\frac{1}{2}) \frac{x ^{2}}{2}

Simplify

cot (\frac{1}{2}) \frac{x ^{2}}{2} : \frac{1}{2} cot (\frac{1}{2}) x^{2}

= \frac{1}{2} cot (\frac{1}{2}) x^{2}

Add a constant to the solution

= \frac{1}{2} cot (\frac{1}{2}) x^{2} + C

What is the integral of cot(1/2)x ?
The integral of cot(1/2)x is 1/2 cot(1/2)x^2+C