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Beliebt Rechnen >

integral of n^2sqrt(4+n)

Lösung

\int n^{2} 4 + n d n

Lösung

\frac{2}{7} (4 + n)^{\frac{7}{2}} - \frac{16}{5} (4 + n)^{\frac{5}{2}} + \frac{32}{3} (4 + n)^{\frac{3}{2}} + C

Schritte zur Lösung

\int n^{2} 4 + n d n

Wende U-Substitution an

= \int (u - 4)^{2} u d u

Multipliziere aus

(u - 4)^{2} u : u^{\frac{5}{2}} - 8 u^{\frac{3}{2}} + 16 u

= \int u^{\frac{5}{2}} - 8 u^{\frac{3}{2}} + 16 u d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int u^{\frac{5}{2}} d u - \int 8 u^{\frac{3}{2}} d u + \int 16 u d u

\int u^{\frac{5}{2}} d u = \frac{2}{7} u^{\frac{7}{2}}

\int 8 u^{\frac{3}{2}} d u = \frac{16}{5} u^{\frac{5}{2}}

\int 16 u d u = \frac{32}{3} u^{\frac{3}{2}}

= \frac{2}{7} u^{\frac{7}{2}} - \frac{16}{5} u^{\frac{5}{2}} + \frac{32}{3} u^{\frac{3}{2}}

Setze in

u = 4 + n

ein

= \frac{2}{7} (4 + n)^{\frac{7}{2}} - \frac{16}{5} (4 + n)^{\frac{5}{2}} + \frac{32}{3} (4 + n)^{\frac{3}{2}}

Füge eine Konstante zur Lösung hinzu

= \frac{2}{7} (4 + n)^{\frac{7}{2}} - \frac{16}{5} (4 + n)^{\frac{5}{2}} + \frac{32}{3} (4 + n)^{\frac{3}{2}} + C

Graph

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