What is the integral of (e^{5x-3}) ?

The integral of (e^{5x-3}) is 1/5 e^{5x-3}+C

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integral of (e^{5x-3})

\int (e^{5 x - 3}) d x

\frac{1}{5} e^{5 x - 3} + C

Solution steps

\int e^{5 x - 3} d x

Apply u-substitution

= \int e^{u} \frac{1}{5} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{5} e^{u}

Substitute back

u = 5 x - 3

= \frac{1}{5} e^{5 x - 3}

Add a constant to the solution

= \frac{1}{5} e^{5 x - 3} + C

What is the integral of (e^{5x-3}) ?
The integral of (e^{5x-3}) is 1/5 e^{5x-3}+C