What is the integral of (x^2+1)/((x+1)(x^2+2x+2)) ?

The integral of (x^2+1)/((x+1)(x^2+2x+2)) is 2ln|x+1|-1/2 ln|x^2+2x+2|-2arctan(x+1)+C

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integral of (x^2+1)/((x+1)(x^2+2x+2))

\int \frac{x ^{2} + 1}{( x + 1 ) ( x ^{2} + 2 x + 2 )} d x

2 ln ∣ x + 1 ∣ - \frac{1}{2} ln x^{2} + 2 x + 2 - 2 arctan (x + 1) + C

Solution steps

\int \frac{x ^{2} + 1}{( x + 1 ) ( x ^{2} + 2 x + 2 )} d x

Take the partial fraction of

\frac{x ^{2} + 1}{( x + 1 ) ( x ^{2} + 2 x + 2 )} : \frac{2}{x + 1} + \frac{- x - 3}{x ^{2} + 2 x + 2}

= \int \frac{2}{x + 1} + \frac{- x - 3}{x ^{2} + 2 x + 2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{2}{x + 1} d x + \int \frac{- x - 3}{x ^{2} + 2 x + 2} d x

\int \frac{2}{x + 1} d x = 2 ln ∣ x + 1 ∣

\int \frac{- x - 3}{x ^{2} + 2 x + 2} d x = - \frac{1}{2} ln x^{2} + 2 x + 2 - 2 arctan (x + 1)

= 2 ln ∣ x + 1 ∣ - \frac{1}{2} ln x^{2} + 2 x + 2 - 2 arctan (x + 1)

Add a constant to the solution

= 2 ln ∣ x + 1 ∣ - \frac{1}{2} ln x^{2} + 2 x + 2 - 2 arctan (x + 1) + C

What is the integral of (x^2+1)/((x+1)(x^2+2x+2)) ?
The integral of (x^2+1)/((x+1)(x^2+2x+2)) is 2ln|x+1|-1/2 ln|x^2+2x+2|-2arctan(x+1)+C