What is the integral of 4xysqrt(x^2+y^2) ?

The integral of 4xysqrt(x^2+y^2) is (4x(x^2+y^2)^{3/2})/3+C

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integral of 4xysqrt(x^2+y^2)

\int 4 x y x^{2} + y^{2} d y

\frac{4 x ( x ^{2} + y ^{2} ) ^{\frac{3}{2}}}{3} + C

Solution steps

\int 4 x y x^{2} + y^{2} d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 x \cdot \int x^{2} + y^{2} y d y

Apply u-substitution

= 4 x \cdot \int u^{2} d u

Apply the Power Rule

= 4 x \frac{u ^{3}}{3}

Substitute back

u = x^{2} + y^{2}

= 4 x \frac{( x ^{2} + y ^{2} ) ^{3}}{3}

Simplify

4 x \frac{( x ^{2} + y ^{2} ) ^{3}}{3} : \frac{4 x ( x ^{2} + y ^{2} ) ^{\frac{3}{2}}}{3}

= \frac{4 x ( x ^{2} + y ^{2} ) ^{\frac{3}{2}}}{3}

Add a constant to the solution

= \frac{4 x ( x ^{2} + y ^{2} ) ^{\frac{3}{2}}}{3} + C

What is the integral of 4xysqrt(x^2+y^2) ?
The integral of 4xysqrt(x^2+y^2) is (4x(x^2+y^2)^{3/2})/3+C