What is the integral of (x^4-5x)/(x^3) ?

The integral of (x^4-5x)/(x^3) is (x^2)/2+5/x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (x^4-5x)/(x^3)

\int \frac{x ^{4} - 5 x}{x ^{3}} d x

\frac{x ^{2}}{2} + \frac{5}{x} + C

Solution steps

\int \frac{x ^{4} - 5 x}{x ^{3}} d x

Expand

\frac{x ^{4} - 5 x}{x ^{3}} : x - \frac{5}{x ^{2}}

= \int x - \frac{5}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x d x - \int \frac{5}{x ^{2}} d x

\int x d x = \frac{x ^{2}}{2}

\int \frac{5}{x ^{2}} d x = - \frac{5}{x}

= \frac{x ^{2}}{2} - (- \frac{5}{x})

Simplify

= \frac{x ^{2}}{2} + \frac{5}{x}

Add a constant to the solution

= \frac{x ^{2}}{2} + \frac{5}{x} + C

What is the integral of (x^4-5x)/(x^3) ?
The integral of (x^4-5x)/(x^3) is (x^2)/2+5/x+C