What is the integral of sqrt(1+(2x(x^2+1)^{1/2))^2} ?

The integral of sqrt(1+(2x(x^2+1)^{1/2))^2} is (2x^3)/3+x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of sqrt(1+(2x(x^2+1)^{1/2))^2}

\int 1 + (2 x (x^{2} + 1)^{\frac{1}{2}})^{2} d x

\frac{2 x ^{3}}{3} + x + C

Solution steps

\int 1 + (2 x (x^{2} + 1)^{\frac{1}{2}})^{2} d x

Simplify

1 + (2 x (x^{2} + 1)^{\frac{1}{2}})^{2} : 1 + 4 x^{2} (x^{2} + 1)

= \int 1 + 4 x^{2} (x^{2} + 1) d x

Expand

4 x^{2} (x^{2} + 1) : 4 x^{4} + 4 x^{2}

= \int 1 + 4 x^{4} + 4 x^{2} d x

Factor

4 x^{4} + 4 x^{2} + 1 : (2 x^{2} + 1)^{2}

= \int (2 x^{2} + 1)^{2} d x

(2 x^{2} + 1)^{2} = ((2 x^{2} + 1)),

assuming

(2 x^{2} + 1) \geq 0

= \int 2 x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x + \int 1 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 1 d x = x

= \frac{2 x ^{3}}{3} + x

Add a constant to the solution

= \frac{2 x ^{3}}{3} + x + C

What is the integral of sqrt(1+(2x(x^2+1)^{1/2))^2} ?
The integral of sqrt(1+(2x(x^2+1)^{1/2))^2} is (2x^3)/3+x+C