What is the integral of (e^x)/(3-2e^x) ?

The integral of (e^x)/(3-2e^x) is -1/2 ln|3-2e^x|+C

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integral of (e^x)/(3-2e^x)

\int \frac{e ^{x}}{3 - 2 e ^{x}} d x

- \frac{1}{2} ln ∣ 3 - 2 e^{x} ∣ + C

Solution steps

\int \frac{e ^{x}}{3 - 2 e ^{x}} d x

Apply u-substitution

= \int - \frac{1}{2 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{2} \cdot \int \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= - \frac{1}{2} ln ∣ u ∣

Substitute back

u = 3 - 2 e^{x}

= - \frac{1}{2} ln ∣ 3 - 2 e^{x} ∣

Add a constant to the solution

= - \frac{1}{2} ln ∣ 3 - 2 e^{x} ∣ + C

What is the integral of (e^x)/(3-2e^x) ?
The integral of (e^x)/(3-2e^x) is -1/2 ln|3-2e^x|+C