What is the integral of (e^{y^2}y) ?

The integral of (e^{y^2}y) is 1/2 e^{y^2}+C

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integral of (e^{y^2}y)

\int (e^{y^{2}} y) d y

\frac{1}{2} e^{y^{2}} + C

Solution steps

\int e^{y^{2}} y d y

Apply u-substitution

= \int \frac{e ^{u}}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= \frac{1}{2} e^{u}

Substitute back

u = y^{2}

= \frac{1}{2} e^{y^{2}}

Add a constant to the solution

= \frac{1}{2} e^{y^{2}} + C

What is the integral of (e^{y^2}y) ?
The integral of (e^{y^2}y) is 1/2 e^{y^2}+C