What is the integral of 1/(sqrt(4-5s)) ?

The integral of 1/(sqrt(4-5s)) is -2/5 sqrt(4-5s)+C

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integral of 1/(sqrt(4-5s))

\int \frac{1}{4 - 5 s} d s

- \frac{2}{5} 4 - 5 s + C

Solution steps

\int \frac{1}{4 - 5 s} d s

Apply u-substitution

= \int - \frac{1}{5 u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \frac{1}{5} \cdot \int \frac{1}{u} d u

Apply the Power Rule

= - \frac{1}{5} \cdot 2 u^{\frac{1}{2}}

Substitute back

u = 4 - 5 s

= - \frac{1}{5} \cdot 2 (4 - 5 s)^{\frac{1}{2}}

Simplify

- \frac{1}{5} \cdot 2 (4 - 5 s)^{\frac{1}{2}} : - \frac{2}{5} 4 - 5 s

= - \frac{2}{5} 4 - 5 s

Add a constant to the solution

= - \frac{2}{5} 4 - 5 s + C

What is the integral of 1/(sqrt(4-5s)) ?
The integral of 1/(sqrt(4-5s)) is -2/5 sqrt(4-5s)+C