What is the integral of 1/(x^2)cos(x) ?

The integral of 1/(x^2)cos(x) is -(cos(x))/x-\Si(x)+C

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integral of 1/(x^2)cos(x)

\int \frac{1}{x ^{2}} cos (x) d x

- \frac{cos ( x )}{x} - Si (x) + C

Solution steps

\int \frac{1}{x ^{2}} cos (x) d x

Simplify

\frac{1}{x ^{2}} cos (x) : \frac{cos ( x )}{x ^{2}}

= \int \frac{cos ( x )}{x ^{2}} d x

Apply Integration By Parts

= - \frac{cos ( x )}{x} - \int \frac{sin ( x )}{x} d x

\int \frac{sin ( x )}{x} d x = Si (x)

= - \frac{cos ( x )}{x} - Si (x)

Add a constant to the solution

= - \frac{cos ( x )}{x} - Si (x) + C

What is the integral of 1/(x^2)cos(x) ?
The integral of 1/(x^2)cos(x) is -(cos(x))/x-\Si(x)+C