integral from 0 to 2pi of |cos(x)|

解

\int_{0}^{2 π} ∣ cos (x) ∣ d x

4

解答ステップ

\int_{0}^{2 π} ∣ cos (x) ∣ d x

絶対数を排除する

= \int_{0}^{\frac{π}{2}} cos (x) d x + \int_{\frac{π}{2}}^{\frac{3 π}{2}} - cos (x) d x + \int_{\frac{3 π}{2}}^{2 π} cos (x) d x

\int_{0}^{\frac{π}{2}} cos (x) d x = 1

\int_{\frac{π}{2}}^{\frac{3 π}{2}} - cos (x) d x = 2

\int_{\frac{3 π}{2}}^{2 π} cos (x) d x = 1

= 1 + 2 + 1

簡素化

= 4