integral from-1 to 1 of (x^2-4)

Lösung

\int_{- 1}^{1} (x^{2} - 4) d x

- \frac{22}{3}

Dezimale

- 7.33333 \dots

Schritte zur Lösung

\int_{- 1}^{1} x^{2} - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} x^{2} d x - \int_{- 1}^{1} 4 d x

\int_{- 1}^{1} x^{2} d x = \frac{2}{3}

\int_{- 1}^{1} 4 d x = 8

= \frac{2}{3} - 8

Vereinfache

\frac{2}{3} - 8 : - \frac{22}{3}

= - \frac{22}{3}

\int_{3}^{\infty} \frac{1}{ln ( x )} d x

\int_{- 1}^{3} (- x^{3} - 5 x + 1) d x

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\int_{1}^{4} 1 + 4 x^{2} d x