integral from 1 to 2 of (x^2-3)^2

Lösung

\int_{1}^{2} (x^{2} - 3)^{2} d x

\frac{6}{5}

Dezimale

1.2

Schritte zur Lösung

\int_{1}^{2} (x^{2} - 3)^{2} d x

Multipliziere aus

(x^{2} - 3)^{2} : x^{4} - 6 x^{2} + 9

= \int_{1}^{2} x^{4} - 6 x^{2} + 9 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{4} d x - \int_{1}^{2} 6 x^{2} d x + \int_{1}^{2} 9 d x

\int_{1}^{2} x^{4} d x = \frac{31}{5}

\int_{1}^{2} 6 x^{2} d x = 14

\int_{1}^{2} 9 d x = 9

= \frac{31}{5} - 14 + 9

Vereinfache

\frac{31}{5} - 14 + 9 : \frac{6}{5}

= \frac{6}{5}

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