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Popular Calculus >

y^'=2y-y^2

Solution

y^{^{'}} = 2 y - y^{2}

Solution

y = \frac{2}{- e ^{- 2 t - c_{1}} + 1}

Solution steps

y^{'} (t) = 2 y - y^{2}

Solve Bernoulli ODE:

y = \frac{2}{- e ^{- 2 t - c_{1}} + 1}

y = \frac{2}{- e ^{- 2 t - c_{1}} + 1}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=2y-y^2 ?
The solution for y^'=2y-y^2 is y= 2/(-e^{-2t-c_{1)}+1}