What is the derivative of-(2x(-x^2+3)/((x^2+1)^3)) ?

The derivative of-(2x(-x^2+3)/((x^2+1)^3)) is -(6(x^4-6x^2+1))/((x^2+1)^4)

What is the first derivative of-(2x(-x^2+3)/((x^2+1)^3)) ?

The first derivative of-(2x(-x^2+3)/((x^2+1)^3)) is -(6(x^4-6x^2+1))/((x^2+1)^4)

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\frac{d}{d x} (- \frac{2 x ( - x ^{2} + 3 )}{( x ^{2} + 1 ) ^{3}})

- \frac{6 ( x ^{4} - 6 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{4}}

Solution steps

\frac{d}{d x} (- \frac{2 x ( - x ^{2} + 3 )}{( x ^{2} + 1 ) ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (\frac{x ( - x ^{2} + 3 )}{( x ^{2} + 1 ) ^{3}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= - 2 \cdot \frac{\frac{d}{d x} ( x ( - x ^{2} + 3 ) ) ( x ^{2} + 1 ) ^{3} - \frac{d}{d x} ( ( x ^{2} + 1 ) ^{3} ) x ( - x ^{2} + 3 )}{( ( x ^{2} + 1 ) ^{3} ) ^{2}}

\frac{d}{d x} (x (- x^{2} + 3)) = - 3 x^{2} + 3

\frac{d}{d x} ((x^{2} + 1)^{3}) = 6 x (x^{2} + 1)^{2}

= - 2 \cdot \frac{( - 3 x ^{2} + 3 ) ( x ^{2} + 1 ) ^{3} - 6 x ( x ^{2} + 1 ) ^{2} x ( - x ^{2} + 3 )}{( ( x ^{2} + 1 ) ^{3} ) ^{2}}

Simplify

- 2 \cdot \frac{( - 3 x ^{2} + 3 ) ( x ^{2} + 1 ) ^{3} - 6 x ( x ^{2} + 1 ) ^{2} x ( - x ^{2} + 3 )}{( ( x ^{2} + 1 ) ^{3} ) ^{2}} : - \frac{6 ( x ^{4} - 6 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{4}}

= - \frac{6 ( x ^{4} - 6 x ^{2} + 1 )}{( x ^{2} + 1 ) ^{4}}

What is the derivative of-(2x(-x^2+3)/((x^2+1)^3)) ?
The derivative of-(2x(-x^2+3)/((x^2+1)^3)) is -(6(x^4-6x^2+1))/((x^2+1)^4)
What is the first derivative of-(2x(-x^2+3)/((x^2+1)^3)) ?
The first derivative of-(2x(-x^2+3)/((x^2+1)^3)) is -(6(x^4-6x^2+1))/((x^2+1)^4)