What is the tangent of f(x)=sqrt(3x+91),(3,10) ?

The tangent of f(x)=sqrt(3x+91),(3,10) is y= 3/20 x+191/20

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tangent of f(x)=sqrt(3x+91),(3,10)

tangent of

f (x) = 3 x + 91, (3, 10)

y = \frac{3}{20} x + \frac{191}{20}

Solution steps

Find the slope of

f (x) = 3 x + 91 : \frac{df ( x )}{d x} = \frac{3}{2 3 x + 91}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{3}{20}

Find the line with slope m=

\frac{3}{20}

and passing through

(3, 10) : y = \frac{3}{20} x + \frac{191}{20}

y = \frac{3}{20} x + \frac{191}{20}

What is the tangent of f(x)=sqrt(3x+91),(3,10) ?
The tangent of f(x)=sqrt(3x+91),(3,10) is y= 3/20 x+191/20