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Popular Calculus >

integral from 0 to 1 of (7x-4)

Solution

\int_{0}^{1} (7 x - 4) d x

Solution

- \frac{1}{2}

+1

Decimal

- 0.5

Solution steps

\int_{0}^{1} 7 x - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 7 x d x - \int_{0}^{1} 4 d x

\int_{0}^{1} 7 x d x = \frac{7}{2}

\int_{0}^{1} 4 d x = 4

= \frac{7}{2} - 4

Simplify

\frac{7}{2} - 4 : - \frac{1}{2}

= - \frac{1}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (7x-4) ?
The integral from 0 to 1 of (7x-4) is -1/2