integral from 0 to 2 of 1/(t-2)

解答

\int_{0}^{2} \frac{1}{t - 2} d t

发散

求解步骤

\int_{0}^{2} \frac{1}{t - 2} d t

使用换元积分法

= \int_{- 2}^{0} \frac{1}{u} d u

使用积分常见定则:

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{- 2}^{0}

带入上下限计算后得:

发散

= 发散

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