integral from 2 to infinity of e^{5-6x}

解答

\int_{2}^{\infty} e^{5 - 6 x} d x

\frac{1}{6 e ^{7}}

十进制

0.00015 \dots

求解步骤

\int_{2}^{\infty} e^{5 - 6 x} d x

计算不定积分:

\int e^{5 - 6 x} d x = - \frac{1}{6} e^{5 - 6 x} + C

带入上下限计算后得:

\int_{2}^{\infty} e^{5 - 6 x} d x = 0 - (- \frac{1}{6 e ^{7}})

= 0 - (- \frac{1}{6 e ^{7}})

化简

= \frac{1}{6 e ^{7}}

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