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Popular Calculus >

integral from 1 to 4 of (3x^2+6)

Solution

\int_{1}^{4} (3 x^{2} + 6) d x

Solution

81

Solution steps

\int_{1}^{4} 3 x^{2} + 6 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} 3 x^{2} d x + \int_{1}^{4} 6 d x

\int_{1}^{4} 3 x^{2} d x = 63

\int_{1}^{4} 6 d x = 18

= 63 + 18

Simplify

= 81

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of (3x^2+6) ?
The integral from 1 to 4 of (3x^2+6) is 81