What is the integral from-2x to 3x^2 of cos(t) ?

The integral from-2x to 3x^2 of cos(t) is sin(3x^2)+sin(2x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from-2x to 3x^2 of cos(t)

\int_{- 2 x}^{3 x^{2}} cos (t) d t

sin (3 x^{2}) + sin (2 x)

Solution steps

\int_{- 2 x}^{3 x^{2}} cos (t) d t

Use the common integral:

\int cos (t) d t = sin (t)

= [sin (t)]_{- 2 x}^{3 x^{2}}

Compute the boundaries:

sin (3 x^{2}) + sin (2 x)

= sin (3 x^{2}) + sin (2 x)

What is the integral from-2x to 3x^2 of cos(t) ?
The integral from-2x to 3x^2 of cos(t) is sin(3x^2)+sin(2x)