What is the integral from 3 to 2 of g(x) ?

The integral from 3 to 2 of g(x) is -(5g)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 3 to 2 of g(x)

\int_{3}^{2} g (x) d x

- \frac{5 g}{2}

Solution steps

\int_{3}^{2} gx d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{2}^{3} gx d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - g \cdot \int_{2}^{3} x d x

Apply the Power Rule

= - g [\frac{x ^{2}}{2}]_{2}^{3}

Compute the boundaries:

\frac{5}{2}

= - g \frac{5}{2}

Simplify

= - \frac{5 g}{2}

What is the integral from 3 to 2 of g(x) ?
The integral from 3 to 2 of g(x) is -(5g)/2