integral from 0 to 2z of-1+x

Lösung

\int_{0}^{2 z} - 1 + x d x

- 2 z + 2 z^{2}

Schritte zur Lösung

\int_{0}^{2 z} - 1 + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2 z} 1 d x + \int_{0}^{2 z} x d x

\int_{0}^{2 z} 1 d x = 2 z

\int_{0}^{2 z} x d x = 2 z^{2}

= - 2 z + 2 z^{2}

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