What is area 4x+8,x^2+19x+62,[-9,-6] ?

The answer to area 4x+8,x^2+19x+62,[-9,-6] is 9/2

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area 4x+8,x^2+19x+62,[-9,-6]

area

4 x + 8, x^{2} + 19 x + 62, [- 9, - 6]

\frac{9}{2}

Decimal

4.5

Solution steps

Apply the area formula:

\int_{- 9}^{- 6} 4 x + 8 - (x^{2} + 19 x + 62) d x

Solve

\int_{- 9}^{- 6} 4 x + 8 - (x^{2} + 19 x + 62) d x : \frac{9}{2}

The area is:

= \frac{9}{2}

What is area 4x+8,x^2+19x+62,[-9,-6] ?
The answer to area 4x+8,x^2+19x+62,[-9,-6] is 9/2