integral from 4 to 12 of sqrt(1+2x)

Lösung

\int_{4}^{12} 1 + 2 x d x

\frac{98}{3}

Dezimale

32.66666 \dots

Schritte zur Lösung

\int_{4}^{12} 1 + 2 x d x

Wende U-Substitution an

= \int_{9}^{25} \frac{u}{2} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{9}^{25} u d u

Wende die Potenzregel an

= \frac{1}{2} [\frac{2}{3} u^{\frac{3}{2}}]_{9}^{25}

Berechne die Grenzen:

\frac{196}{3}

= \frac{1}{2} \cdot \frac{196}{3}

Vereinfache

= \frac{98}{3}

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