integral from-1 to 3 of x^3-9x

解答

\int_{- 1}^{3} x^{3} - 9 x d x

- 16

求解步骤

\int_{- 1}^{3} x^{3} - 9 x d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{3} x^{3} d x - \int_{- 1}^{3} 9 x d x

\int_{- 1}^{3} x^{3} d x = 20

\int_{- 1}^{3} 9 x d x = 36

= 20 - 36

化简

= - 16

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