integral from e to 2e of 1/(xln^2(x))

Lösung

\int_{e}^{2 e} \frac{1}{x ln ^{2} ( x )} d x

- \frac{1}{ln ( 2 e )} + 1

Dezimale

0.40938 \dots

Schritte zur Lösung

\int_{e}^{2 e} \frac{1}{x ln ^{2} ( x )} d x

Wende U-Substitution an

= \int_{1}^{l n (2 e)} \frac{1}{u ^{2}} d u

Wende die Potenzregel an

= [- \frac{1}{u}]_{1}^{l n (2 e)}

Berechne die Grenzen:

- \frac{1}{ln ( 2 e )} + 1

= - \frac{1}{ln ( 2 e )} + 1

\int_{0}^{1} \frac{3}{5} x d x

\int_{1}^{0} x^{3} e^{2 x} d x

\int_{0}^{1} y - y d y

\int_{0}^{1} \frac{x}{1 + e ^{- x^{2}}} d x

\int_{0}^{π} sin (x + k x) d x