integral from 3 to 7 of 4(x-5)^3

Lösung

\int_{3}^{7} 4 (x - 5)^{3} d x

0

Schritte zur Lösung

\int_{3}^{7} 4 (x - 5)^{3} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{3}^{7} (x - 5)^{3} d x

Wende U-Substitution an

= 4 \cdot \int_{- 2}^{2} u^{3} d u

Wende die Potenzregel an

= 4 [\frac{u ^{4}}{4}]_{- 2}^{2}

Berechne die Grenzen:

0

= 4 \cdot 0

Vereinfache

= 0

\int_{5}^{\infty} x e^{- \frac{x}{2}} d x

\int_{1}^{2} x^{3} - 2 x^{2} - 5 x + 6 d x

\int_{0}^{1} 2 y^{2} - 2 y d y

\int_{- 8}^{3} 1 + ∣ x ∣ d x

\int_{- 2}^{1} (x^{2} + 1)^{2} d x