integral from-1 to 1 of (3x+2)

Lösung

\int_{- 1}^{1} (3 x + 2) d x

4

Schritte zur Lösung

\int_{- 1}^{1} 3 x + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 3 x d x + \int_{- 1}^{1} 2 d x

\int_{- 1}^{1} 3 x d x = 0

\int_{- 1}^{1} 2 d x = 4

= 0 + 4

Vereinfache

= 4

\int_{0}^{π} x^{3} sin (3 x) d x

\int_{1}^{4} (- 3 x) d x

\int_{0}^{4} \frac{1}{( x - 1 ) ^{\frac{1}{3}}} d x

\int_{1}^{\infty} \frac{2}{3 x + 4} d x

\int_{- 2}^{1} x^{2} + x + 2 d x