integral from 0 to 4 of (x^2-8x+16)/(16)

Lösung

\int_{0}^{4} \frac{x ^{2} - 8 x + 16}{16} d x

\frac{4}{3}

Dezimale

1.33333 \dots

Schritte zur Lösung

\int_{0}^{4} \frac{x ^{2} - 8 x + 16}{16} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{16} \cdot \int_{0}^{4} x^{2} - 8 x + 16 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{16} (\int_{0}^{4} x^{2} d x - \int_{0}^{4} 8 x d x + \int_{0}^{4} 16 d x)

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 8 x d x = 64

\int_{0}^{4} 16 d x = 64

= \frac{1}{16} (\frac{64}{3} - 64 + 64)

Vereinfache

\frac{1}{16} (\frac{64}{3} - 64 + 64) : \frac{4}{3}

= \frac{4}{3}

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