integral from-1 to 2 of 2x^2-4x+5

Lösung

\int_{- 1}^{2} 2 x^{2} - 4 x + 5 d x

15

Schritte zur Lösung

\int_{- 1}^{2} 2 x^{2} - 4 x + 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 2 x^{2} d x - \int_{- 1}^{2} 4 x d x + \int_{- 1}^{2} 5 d x

\int_{- 1}^{2} 2 x^{2} d x = 6

\int_{- 1}^{2} 4 x d x = 6

\int_{- 1}^{2} 5 d x = 15

= 6 - 6 + 15

Vereinfache

= 15

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