integral from 0 to 0.4 of x

Lösung

\int_{0}^{0.4} x d x

0.08

Schritte zur Lösung

\int_{0}^{0.4} x d x

Wende die Potenzregel an

= [\frac{x ^{2}}{2}]_{0}^{0.4}

Vereinfache

= [0.5 x^{2}]_{0}^{0.4}

Berechne die Grenzen:

0.08

= 0.08

\int_{0}^{1} ln (x + 10) d x

\int_{t}^{2} - x ln (x - 1) d x

\int_{1}^{4} 4 t^{2} d t

\int_{2}^{0} 2 x d x

\int_{- 1.6}^{0} π ((6 x - x^{2}))^{2} d x