integral from 0 to 5 of 3x+2

解答

\int_{0}^{5} 3 x + 2 d x

\frac{95}{2}

十进制

47.5

求解步骤

\int_{0}^{5} 3 x + 2 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5} 3 x d x + \int_{0}^{5} 2 d x

\int_{0}^{5} 3 x d x = \frac{75}{2}

\int_{0}^{5} 2 d x = 10

= \frac{75}{2} + 10

化简

\frac{75}{2} + 10 : \frac{95}{2}

= \frac{95}{2}

\int_{2}^{3} 3 t^{2} + 1 d t

\int_{0}^{12} \frac{1}{1 + x ^{2}} d x

\int_{3}^{\infty} \frac{3}{x ^{6}} d x

\int_{3}^{5} 3 + x^{2} d x

\int_{2}^{5} \frac{1}{( x + 2 ) ( x + 5 )} d x