What is area 2x^2+4x-2,0,2 ?

The answer to area 2x^2+4x-2,0,2 is 12sqrt(2)+(44-20sqrt(2))/3-12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

area 2x^2+4x-2,0,2

area

2 x^{2} + 4 x - 2, 0, 2

122 + \frac{44 - 20 2}{3} - 12

Decimal

10.20913 \dots

Solution steps

Apply the area formula:

\int_{0}^{2} 2 x^{2} + 4 x - 2 d x

Solve

\int_{0}^{2} 2 x^{2} + 4 x - 2 d x : 122 + \frac{44 - 20 2}{3} - 12

The area is:

= 122 + \frac{44 - 20 2}{3} - 12

What is area 2x^2+4x-2,0,2 ?
The answer to area 2x^2+4x-2,0,2 is 12sqrt(2)+(44-20sqrt(2))/3-12