integral of (3/(u^2)+4/(u^3)-2)

Lösung

\int (\frac{3}{u ^{2}} + \frac{4}{u ^{3}} - 2) d u

- \frac{3}{u} - \frac{2}{u ^{2}} - 2 u + C

Schritte zur Lösung

\int \frac{3}{u ^{2}} + \frac{4}{u ^{3}} - 2 d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{3}{u ^{2}} d u + \int \frac{4}{u ^{3}} d u - \int 2 d u

\int \frac{3}{u ^{2}} d u = - \frac{3}{u}

\int \frac{4}{u ^{3}} d u = - \frac{2}{u ^{2}}

\int 2 d u = 2 u

= - \frac{3}{u} - \frac{2}{u ^{2}} - 2 u

Füge eine Konstante zur Lösung hinzu

= - \frac{3}{u} - \frac{2}{u ^{2}} - 2 u + C

y^{^{''}} - 4 y^{^{'}} = sin (3 x)

d er i v a t i v e 7 x^{6} - 4 x^{5}

\int cos (2 x) + sin (x) d x

\int 10000 - x^{2} d x

a re a y = x^{2} - 4 x, y = - 2 x