What is the integral of (2x^{1/2}) ?

The integral of (2x^{1/2}) is 4/3 x^{3/2}+C

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integral of (2x^{1/2})

\int (2 x^{\frac{1}{2}}) d x

\frac{4}{3} x^{\frac{3}{2}} + C

Solution steps

\int 2 x^{\frac{1}{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x^{\frac{1}{2}} d x

Apply the Power Rule

= 2 \cdot \frac{2}{3} x^{\frac{3}{2}}

Simplify

2 \cdot \frac{2}{3} x^{\frac{3}{2}} : \frac{4}{3} x^{\frac{3}{2}}

= \frac{4}{3} x^{\frac{3}{2}}

Add a constant to the solution

= \frac{4}{3} x^{\frac{3}{2}} + C

What is the integral of (2x^{1/2}) ?
The integral of (2x^{1/2}) is 4/3 x^{3/2}+C