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人気のある微分積分 >

integral from 0 to a of (bcos(cx)+

解

\int_{0}^{a} (b cos (c x) + d) d x

解

\frac{b sin ( c a )}{c} + d a

解答ステップ

\int_{0}^{a} b cos (c x) + dd x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{a} b cos (c x) d x + \int_{0}^{a} dd x

\int_{0}^{a} b cos (c x) d x = \frac{b sin ( c a )}{c}

\int_{0}^{a} dd x = d a

= \frac{b sin ( c a )}{c} + d a

人気の例

integral from 2 to 3 of 1/(x^3+2x)

\int_{2}^{3} \frac{1}{x ^{3} + 2 x} d x

integral from-2 to 2 of (3xy^2)/(x^2+1)

\int_{- 2}^{2} \frac{3 x y ^{2}}{x ^{2} + 1} d y

integral from 1 to 3 of sin(r^2)r

\int_{1}^{3} sin (r^{2}) r d r

integral from 0 to 1 of (1/(x+2))

\int_{0}^{1} (\frac{1}{x + 2}) d x

integral from x to 1 of ysqrt(1+x^2-y^2)

\int_{x}^{1} y 1 + x^{2} - y^{2} d y