integral from-2 to 5 of (x+1)

Lösung

\int_{- 2}^{5} (x + 1) d x

\frac{35}{2}

Dezimale

17.5

Schritte zur Lösung

\int_{- 2}^{5} x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{5} x d x + \int_{- 2}^{5} 1 d x

\int_{- 2}^{5} x d x = \frac{21}{2}

\int_{- 2}^{5} 1 d x = 7

= \frac{21}{2} + 7

Vereinfache

\frac{21}{2} + 7 : \frac{35}{2}

= \frac{35}{2}

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