What is the tangent of f(x)=sec(x),\at x=(pi/3) ?

The tangent of f(x)=sec(x),\at x=(pi/3) is y=2sqrt(3)x+2-(2pi)/(sqrt(3))

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tangent of f(x)=sec(x),\at x=(pi/3)

tangent of

f (x) = sec (x), at x = (\frac{π}{3})

y = 23 x + 2 - \frac{2 π}{3}

Solution steps

Find the tangent point:

(\frac{π}{3}, 2)

Find the slope of

f (x) = sec (x) : \frac{df ( x )}{d x} = sec (x) tan (x)

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 23

Find the line with slope m=

23

and passing through

(\frac{π}{3}, 2) : y = 23 x + 2 - \frac{2 π}{3}

y = 23 x + 2 - \frac{2 π}{3}

What is the tangent of f(x)=sec(x),\at x=(pi/3) ?
The tangent of f(x)=sec(x),\at x=(pi/3) is y=2sqrt(3)x+2-(2pi)/(sqrt(3))