integral from-1 to 2 of (x^2+4x+6)

Lösung

\int_{- 1}^{2} (x^{2} + 4 x + 6) d x

27

Schritte zur Lösung

\int_{- 1}^{2} x^{2} + 4 x + 6 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} x^{2} d x + \int_{- 1}^{2} 4 x d x + \int_{- 1}^{2} 6 d x

\int_{- 1}^{2} x^{2} d x = 3

\int_{- 1}^{2} 4 x d x = 6

\int_{- 1}^{2} 6 d x = 18

= 3 + 6 + 18

Vereinfache

= 27