integral from 1 to 3 of x^2-4x+6

Lösung

\int_{1}^{3} x^{2} - 4 x + 6 d x

\frac{14}{3}

Dezimale

4.66666 \dots

Schritte zur Lösung

\int_{1}^{3} x^{2} - 4 x + 6 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{2} d x - \int_{1}^{3} 4 x d x + \int_{1}^{3} 6 d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} 4 x d x = 16

\int_{1}^{3} 6 d x = 12

= \frac{26}{3} - 16 + 12

Vereinfache

\frac{26}{3} - 16 + 12 : \frac{14}{3}

= \frac{14}{3}